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\[2x^2(4x^2  5) = 18\]
if x > 0, what is the solution to the equation above?
Solution:
Solve for Zero Product Property: 4y  9 or y + 1 = 0; therefore, y = 9/4 or y = 1
Since x is a real number, x^2 = 1 has no solutions. And if x must by positive, then the solution to x^2 = 9/4 is x = 3/2 or x = 1.5.
Final Answer: x = 1.5
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