Problem:If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)? Solution:
Formula: vf^2 – vi^2 = 2ad (0 m/s)2 = vi^2 + 2*(9.8 m/s2)*(1.29 m) 0 m2/s2 = vi^2  25.28 m2/s2 25.28 m2/s2 = vi^2 vi = 5.03 m/s To find hang time, find the time to the peak and then double it. Formula: vf = vi + a*t 0 m/s = 5.03 m/s + (9.8 m/s2)*t
5.03 m/s = (9.8 m/s2)*t (5.03 m/s)/(9.8 m/s2) = t t = 0.513 s hang time = 1.03 s
1 Comment
Timothy
3/22/2019 10:48:39 am
Hello thx sirie :)
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