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January 2018
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Problem:What is the smallest possible value for a where y = sin 2a reaches its maximum? A. π /4 B. π /2 C. π D. 2π E. 4π Answer:The correct answer is A.
To solve this problem, you must first recall that the maximum value of the sine function is 1, and that the smallest value for a at this maximum value will be π./2. So, if 2a = π/2, then a = π/4 .
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