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What is the smallest possible value for a where y = sin 2a reaches its maximum?
A. π /4
B. π /2
The correct answer is A.
To solve this problem, you must first recall that the maximum value of the sine function is 1, and that the smallest value for a at this maximum value will be π./2. So, if 2a = π/2, then a = π/4 .
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