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2y + 6x = 3
y + 3x = 2
How many solutions (x, y) are there to the system of equations above?
D) More than two
If you multiply each side of y + 3x = 2 by 2, you get 2y + 6x = 4. Then subtracting each side of 2y + 6x = 3 from the corresponding side of 2y + 6x = 4 gives 0 = 1. This is a false statement. Therefore, the system has zero solutions (x, y).