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Question2y + 6x = 3 y + 3x = 2 How many solutions (x, y) are there to the system of equations above? A) Zero B) One C) Two D) More than two AnswerIf you multiply each side of y + 3x = 2 by 2, you get 2y + 6x = 4. Then subtracting each side of 2y + 6x = 3 from the corresponding side of 2y + 6x = 4 gives 0 = 1. This is a false statement. Therefore, the system has zero solutions (x, y).
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