The first term in a geometric sequence is 64, and the common ratio is 1/4. For what value of n is
\[t_n = \frac{1}{4}\]
Answer: A geometric series is represented as
\[t_1, t_1r, t_1r^2, t_1r^3, ......, t_1r^{n1} = t_n\]
\[\frac{1}{4} = 64(\frac{1}{4})^{n1}\]
\[4^{n2} = 4^3\]
n = 5
Final Answer: n = 5
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