A fair six-sided die is rolled twice. What is the probability that the first roll produces a 2 and the second roll does NOT produce a 4?

(A) 1/36

(B) 1/18

(C) 5/36

(D) 1/6

(E) 1/3

(A) 1/36

(B) 1/18

(C) 5/36

(D) 1/6

(E) 1/3

**Solution:**

This question deals with the probability of independent events. To summarize:

*If event A is independent of event B, then the probability of event A occurring AND the probability of event B occurring is P(A) • P(B).*

First, find the probabilities of each event occurring:

P(A), the probability that the first roll produces a 2 = ⅙

P(B), the probability that the second roll does NOT produce a 4 = ⅚

Then, multiply: P(A) • P(B) = ⅙ • ⅚ = 5/36.

**T**

**he answer is (C)**.