If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)?
Formula: vf^2 – vi^2 = 2ad
(0 m/s)2 = vi^2 + 2*(-9.8 m/s2)*(1.29 m)
0 m2/s2 = vi^2 - 25.28 m2/s2
25.28 m2/s2 = vi^2
vi = 5.03 m/s
To find hang time, find the time to the peak and then double it.
Formula: vf = vi + a*t
0 m/s = 5.03 m/s + (-9.8 m/s2)*t
-5.03 m/s = (-9.8 m/s2)*t
(-5.03 m/s)/(-9.8 m/s2) = t
t = 0.513 s
hang time = 1.03 s
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